The formula for wind chill (in degrees Fahrenheit) is given byC = 35.74 + 0.6215T ? 35.75v0.16 + 0.4275Tv0.16 where is the wind speed in miles per hour and is the temperature in degrees F. The wind speed is miles per hour and the temperature is 8° ± 3°. Use dC to estimate the maximum possible propagated error and relative error in calculating the wind chill. dC= ± . dC/C= ± .

dC =0.6899T + 30.02

dC/C = (0.6899T + 30.02)/(35.74 + 0.6215T - 35.75V^0.16 + 0.4275Tv^0.16

Step-by-step explanation:

C= 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16

dC = 35.74 + 0.6215T - (35.75×0.16) +:(0.4275×0.16)

dC = 35.74 + 0.6215T - 5.72 + 0.684T

dC = 0.6899T + 30.02

dC/C = (0.6899 + 30.02)/(35.74 + 0.6215T - 35.75Tv^0.16 + 0.4275Tv^0.16

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

try soting them out first

step-by-step explanation: