Use inverse trigonometric functions to solve the following equations. If there is more than one solution, enter all solutions as a comma-separated list (like "1, 3"). If an equation has no solutions, enter "DNE".solve tan ( θ ) = 1 tan(θ)=1 for θ θ (where 0 ≤ θ < 2 π 0≤θ< 2π).

Step-by-step explanation:

tan(θ)=1 for 0 ≤ θ < 2π

θ=

θ =

Tan θ is also positive in the 3rdvq Quadrant,

The Value of θ in the 3rd Quadrant

=

=

Therefore that values of θ in the interval 0 ≤ θ < 2π that satisfies tan(θ)=1 are:

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8