Suppose X is the time it takes a randomly chosen clerical worker in an office to type and send a standard letter of recommendation. Suppose X has a normal distribution, and assume the mean is 10.5 minutes and the standard deviation 3 minutes. You take a random sample of 50 clerical workers and measure their times. What is the chance that their average time is less than 9.5 minutes?

The chance that their average time is less than 9.5 minutes is 0.0094

Step-by-step explanation:

X is the time it takes a randomly chosen clerical worker in an office to type and send a standard letter of recommendation

We are given that X has a normal distribution

Mean = 10.5 minutes

Standard deviation = 3 minutes

n = 50

We are supposed to find the chance that their average time is less than 9.5 minutes i.e. P(X<9.5 minutes)

Formula :

Z = −2.35

Refer the z table for p value

p value=0.0094

So, P(X<9.5)=P(Z<−2.35)=0.0094

Hence  the chance that their average time is less than 9.5 minutes is 0.0094.

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step-by-step explanation:

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.