For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the function
d(v) = v + \frac{v^{2}}{25}
where d is measured in feet. Kerry wants her stopping distance not to exceed 185 ft. At what range of speeds can she travel? (Assume v is positive. Round your values to one decimal place. Enter your answer using interval notation.)

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076

its line 2 i just added the rest or else it wouldn't let me answer