Find the center, vertices, and foci of the ellipse with equation 2x2 + 6y2 = 12.
Center: (0, 0); Vertices: (-V6,0),(V6,0); Foci: (-2, 0), (2,0)
Center: (0, 0); Vertices: (0, -6), (0, 6);
Center: (0, 0); Vertices: (0, -16),(0,16); Foci: (0, -2), (0, 2)
Center: (0, 0); Vertices: (-6, 0), (6, 0);

Centre: (0,0); vertices: (-√6,0),(√6,0); foci: (-2,0), (2,0)  

Step-by-step explanation:

2x² + 6y² = 12

We must convert this to the standard form of an ellipse

h = 0; k = 0; a = √6; b = √2

The centre is at (h,k) = (0,0)

a > b, so the major axis along the x-axis

The vertices are at (±a,0), that is, they are at (-√6,0) and (√6,0).

c² = a² - b² = 6 - 2 = 4

c = 2

The foci are at (-2,0) and (2,0).

The graph of your ellipse shows the centre at (0,0), the vertices at (-√6,0) and (√6,0), and the foci at (-2,0) and (2,0).

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

y=1/4x-4

step-by-step explanation: