Which of the following is a foci of x2/16-y2/4 ? (2√5, 0) (0, 2√5) (2√3, 0)

foci of is . correct option a.

Step-by-step explanation:

Complete equation of Hyperbola for the above question is x2/16-y2/4  = 1 or  , Simplify each term in the equation in order to set the right side equal to  1 . The standard form of an ellipse or hyperbola requires the right side of the equation be  1 . This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola:

a=4 , b = 2, h = 0 , k= 0

Find the distance from the center to a focus of the hyperbola by using the following formula:

Substitute the value of  a  and  b  in the formula.

=

The first focus of a hyperbola can be found by adding  c  to  h

(h+c,k)

Substitute the known values of h ,  c , and  k into the formula and simplify:

. ∴ foci of is . correct option a.

(2√5, 0)

Step-by-step explanation: got it right

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!