18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same principal apply in scale for other numbers are they x2 , You can try one or two different numbers to 120 ones. Not asking for the individual factors just how many for your example 2 numbers one must be x 10 of itself like 120:1200 is.

Explanation:

Your premise and conclusion are both incorrect.

120 has the prime factorization ...

  120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

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1200 has the same prime factor and two more: 2·5, so the factorization is ...

  1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

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When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

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Summary

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

For reference

Here are the divisors of 120:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.