The range R and the maximum height H of a projectile fired at an inclination θ
to the horizontal with initial speed v0
are given by the formulas below, where g≈32.2 feet per second per second is the acceleration due to gravity.

R≈1369.5652

Find the range H if the projectile is fired at an angle of 45° to the horizontal with an initial speed of 210 feet per second.

342 feet in 3sf

Step-by-step explanation:

H = 210² × (sin(45))²/(2×32.2)

= 22050/64.4

= 342.3913043478

i am unable to solve this problem

step-by-step explanation:

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870