Find the VERTEX of the parabola f(x) = x^2 - 16x + 63

vertex = (8, - 1 )

Step-by-step explanation:

Given a parabola in standard form, f(x) = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

= -

f(x) = x² - 16x + 63 ← is in standard form

with a = 1 and b = - 16, thus

= - = 8

Substitute x = 8 into f(x)

f(8) = 8² - 16(8) + 63 = 64 - 128 + 63 = - 1

vertex = (8, - 1 )

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

answer: it's d

step-by-step explanation: