Cora is playing a game that involves flipping three coins at once. Let the random variable HHH be the number of coins that land showing "heads". Here is the probability distribution for HHH: H= \# \text{ of heads}H=# of headsH, equals, \#, start text, space, o, f, space, h, e, a, d, s, end text 000 111 222 333 P(H)P(H)P, left parenthesis, H, right parenthesis 0.1250.1250, point, 125 0.3750.3750, point, 375 0.3750.3750, point, 375 0.1250.1250, point, 125 P(H < 3)=P(H<3)=P, left parenthesis, H, is less than, 3, right parenthesis, equals

0.875

Step-by-step explanation:

P(H=0) = 0.125

P(H=1) = 0.375

P(H=2) = 0.375

P(H=3) = 0.125

P(H<3) = P(H=0) + P(H=1) + P(H=2)

P(H<3) = 0.125 + 0.375 + 0.375

P(H<3) = 0.875

mark other person brainliest

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;