R(x)=f(x)+g(x) where f(x)=2x2+7x−28x2−16 and g(x)=7x+4−x2+16

R(X) = -27x^2 + 14x + 4

Step-by-step explanation:

f(x) = 2x^2 + 7x - 28x^2 - 16

Combine like terms

f(x) = -26x^2 + 7x - 16

now for g(x)

g(x) = 7x + 4 - x^2 + 16

g(x) = -x^2 + 7x + 20

Now to solve the main equation

R(x) = --26x^2 + 7x - 16 - x^2 + 7x + 20

Combine like terms

R(x) = -27x^2 + 14x + 4

Hope this helped!

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v