A rectangle has a perimeter of 76. if the width is five more than twice the length find the width and length

The width is 27, while the length is 11.

Step-by-step explanation: If the width is five more than twice the length, and the length is given as L, then the width can be expressed as

5 + 2 x L

= 5 + 2L

If the perimeter is 76, and the perimeter of a rectangle is given as

Perimeter = 2(L + W), then

Perimeter = 2(L + 5 + 2L)

Perimeter = 2(3L + 5)

76 = 6L + 10

Subtract 10 from both sides of the equation

66 = 6L

Divide both sides of the equation by 6

L = 11

Having calculated the value of L, the width can now be computed as follows

W = 5 + 2L

W = 5 + 2(11)

W = 5 + 22

W = 27

Hence the dimensions are, Length = 11 and Width = 27.

20

step-by-step explanation:

i believe the answer is c.