An election ballot asks voters to select four city commissioners from a group of sixteen candidates. In how many ways can this be done?

1820

Step-by-step explanation:

The first can be selected in 16 ways, the second in 15 ways, the third in 14 ways and the last in 13 ways

i.e. 16 x 15 x 14 x 13 => 43680

However, the order of the candidates does not matter and they can be selected in 4 x 3 x 2 x 1 => 24 ways

so, 43680/24 => 1820

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

b

step-by-step explanation: