A homeowner plants 6 bulbs selected at random from a box containing 5 tulip bulbs and 4 daffodil bulbs. What is the probability that he planted 2 daffodil bulbs and 4 tulip bulbs?

Required probability = 0.3571

Step-by-step explanation:

We are given that a homeowner plants 6 bulbs selected at random from a box containing 5 tulip bulbs and 4 daffodil bulbs.

Number of ways of selecting 2 daffodil bulbs from total of 4 daffodil bulbs is given by = = = 6

Number of ways of selecting 4 tulip bulbs from total of 5 tulip bulbs is given by = = = 5

And Number of ways of selecting 6 bulbs from total of 9 bulbs in the box is given by = = = 84

So, probability that he planted 2 daffodil bulbs and 4 tulip bulbs =

                                   =   = 30/84 = 0.3571

Therefore, required probability = 0.3571.

1 is c

2 is a

3 is a

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)