I need help with these three problems please

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

Thus, the perimeter of the square is

Q9. Equilateral triangles have 3 equal sides and each interior angle is 60°.

Since the perimeter of the equilateral triangle is 126cm,

length of each side= 126÷3 = 42 cm

The green line drawn in picture 3 is the altitude of the triangle.

Let the altitude of the triangle be x cm.

sin 60°=

(to 3 s.f.)

Therefore, the length of the altitude of the triangle is 36.4cm.

7) 8sqrt(2) in

8) 68sqrt(2) ft

9) 21sqrt(3) cm

Step-by-step explanation:

7) sqrt(8² + 8²) = 8sqrt(2) in

sqrt is square root

8) sqrt(x² + x²) = 34

2x² = 34²

x = 17sqrt(2)

Perimeter = 4x = 68sqrt(2) ft

9) 3s = 126

s = 42

Altitude² + 21² = 42²

Altitude² = 1323

Altitude = 21sqrt(3) cm

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)