If a snowball melts so that its surface area decreases at a rate of 5 cm2/min, find the rate at which the diameter decreases when the diameter is 11 cm. (Give your answer correct to 4 decimal places.) cm/min

0.0723 cm/min

Step-by-step explanation:

A snowball is spherical, so it's area is given by the following formula:

The radius is half the diameter, so:

If a snowball melts so that its surface area decreases at a rate of 5 cm2/min, find the rate at which the diameter decreases when the diameter is 11 cm.

This is when

Applying implicit differentiation:

We have to variables(A and d), so:

So the answer is

0.0723 cm/min

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

step-by-step explanation:

where is the question is there is a formula or is there not one