In a certain game of chance, your chances of winning are 0.2. Assume outcomes are independent and that you will play the game five times. What is the probability that you win at most once

73.73% probability that you win at most once

Step-by-step explanation:

For each game that you play, there are only two possible outcomes. Either you win, or you lose. The games are independent from each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In a certain game of chance, your chances of winning are 0.2.

This means that

Assume outcomes are independent and that you will play the game five times.

This means that

What is the probability that you win at most once

73.73% probability that you win at most once

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

nlgqer

step-by-step