A study reported that finger rings increase the growth of bacteria on health-care workers' hands. Research suggests that 31 percent of health-care workers who wear rings have bacteria on one or both hands, and 27 percent of health-care workers without rings have bacteria on one or both hands. Suppose that independent random samples of 100 health-care workers wearing rings and 100 health-care workers not wearing rings are selected. What is the standard deviation of the sampling distribution of the difference in the sample proportions (wear rings minus does not wear rings) of health-care workers having bacteria on one or both hands?

Despite some evidence that suggest that finger ring use is associated with higher bacterial

colonization, healthcare providers continue to wear finger rings in a healthcare setting. The aim

of this systematic review was to synthesize the evidence to date regarding whether finger ring

use increases bacterial colonization of healthcare providers' hands. Articles that studied the

association finger ring use with hand hygiene and bacterial colonization were searched using

PubMed, Google Scholar, and Georgia State University's online library systems. The overall

results of this review suggest that finger ring use does increase the bacterial colonization on the

hands of HCPs but not with significant difference when compared to no finger ring use;

therefore, further research needs to be conducted to decide whether finger rings should be used in

a healthcare setting or not.

Help me Really !

Step-by-step explanation:

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."