When graphed, which function has a horizontal asymptote at 4?

A.
f(x) = 2x − 4
B.
f(x) = -3x + 4
C.
f(x) = 2(3)x + 4
D.
f(x) = 3(2)x − 4

Correct C. f(x) = 2(3)x + 4

(please note we changed the expression of the function to exponential form which we believe is the correct form of the question)

Step-by-step explanation:

Horizontal Asymptote

The graph of a function is said to have a horizontal asymptote at y=a if one or both the following limits exist

The horizontal asymptotes are horizontal lines to which the function tends when x increases or decreases without limits.

Let's analyze each one of the options provided:

A.  f(x) = 2x -4

No horizontal asymptote

B.  f(x) = -3x + 4

No horizontal asymptote

C. f(x) = 2\cdot 3^x + 4

This function has a horizontal asymptote at y=4

D. 3\cdot 2^x -4

This function has a horizontal asymptote at y=-4

Correct C.

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

answer: it's upside down and i can't read it

step-by-step explanation: