I forgot how to do this stuff-

Solve the system of equations. Show your work.

y=x^2-3x+4
x+y=4

x = 2

y = 2

Step-by-step explanation:

The given system of equations is expressed as

y = x²- 3x + 4- - - - - - - - - - - - -1

x + y = 4- - - - - - - - - - - -2

We would the method of substitution by substituting equation 1 into equation 2. It becomes

x + x²- 3x + 4 = 4- - - - - - - - - - -3

x² + x - 3x + 4 = 4

x² - 2x + 4 = 4

Subtracting 4 from the left hand side and the right hand side of the equation, it becomes

x² - 2x + 4 - 4 = 4 - 4

x² - 2x = 0

Adding 2x to the left hand side and the right hand side of the equation, it becomes

x² - 2x + 2x = 0 + 2x

x² = 2x

Dividing the left hand side and the right hand side of the equation by x, it becomes

x²/x = 2x/x

x = 2

Substituting x = 2 into equation 1, it becomes

y = 2²- 3 × 2 + 4

y = 4 - 6 + 4

y = 2

what is the information provided?

step-by-step explanation: