Suppose you toss a volleyball to a friend who is 12 ft away. Midway between you and your friend is a volleyball net, the top of which is 7 ft high. The ceiling of the gymnasium is 25 ft high. When you toss the ball to your friend, the shape of its path forms a parabola. The volleyball is 4 ft off the floor when it leaves your hands, and your friend catches the volleyball 4 ft off the floor as well. Write the equation that models the path of the volleyball if it passes midway between the net and the ceiling. Assume the origin is at the base of the volleyball net. Include the vertex, focus, and directrix of the parabola plz thx

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b

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plz mark brainliest