Assume there is probability of 0.36 that a U. S. soldier who served in the last decade has served in Iraq. If a soldier served in the last decade and was in Iraq, suppose there is a probability of 0.14 the person developed lung problems. However, if the soldier served in the last decade and was not in Iraq, suppose there is a 0.10 probability the person developed lung problems. If a soldier who served in the last decade developed lung problems, what is the probability the soldier served in Iraq?

0.440559

Step-by-step explanation:

To find the probability of having a soldier from Iraq that had lung problems, we multiply the 2 probabilities, so 0.36*0.14 = 0.0504

The probability of a soldier serving not in Iraq and having lung problems is 0.64 (serving in Iraq is 0.36, so not serving in Iraq is 1 - 0.36 = 0.64) times 0.1 = 0.064.

If we sum up these two probabilities, we have the probability of a soldier having lung problems (0.0504+0.064 = 0.1144).

Now, to know the probability of a soldier with a lung problem having served on Iraq, we divide the probability of serving in Iraq and having lung problems (0.0504) by the probability of having lung problem (0.1144):

0.0504/0.1144 = 0.440559

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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