The stopping distance of a car varies directly as the square of its speed. If a car traveling at 20mph requires 25.5ft to stop, find the stopping distance for a car traveling at 50mph.

159.375 feet.

Step-by-step explanation:

Let d represent stopping distance of a car and s represent speed of car.

We have been given that the stopping distance of a car varies directly as the square of its speed.

We know that two directly proportional quantities are in form , where y is directly proportional to x and k is constant of proportionality.

We can represent our given information in an equation as:

.

We are also told that a car traveling at 20 mph requires 25.5 ft to stop. We can represent this information in our equation as:

Now, we will substitute and in our equation and solve for d as:

Therefore, a car traveling at 50 mph requires 159.375 feet to stop.

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?