Urn contains 10 red balls and 5 green balls. A ball is drawn from the urnat random with replacement. If the ball is red, another red ball is added to theurn; if it is green, two more green balls are added to the urn. Then again a ballis drawn at random. Given that a red ball has been picked up in the seconddraw, what is the probability that a green ball was picked in the first draw

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

step-by-step explanation:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

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