Please help. Picture included

3yz²-4y²z+6y³-2z³

First group the terms with the coefficients 3 and 6 and 4 and 2 together.

3yz²+6y³-4y²z-2z³

And then factor the GCF from the first two terms and the last two.

3y(z²+2y²)-2z(2y²+z²)  The two binomials match so we can group 3y and -2z

(3y-2z)(z²+2y²)

C

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!