A jet is coming in for a landing. It's currently 25,000 feet in
the air and the landing strip is 45,000 feet directly ahead. In
order to ensure a safe landing the plane needs to come in at no
more than a 30° angle of depression. Will this be a safe
landing?
Is this a safe landing?

The angle of depression is 29.0521°. So it is a safe landing.

Step-by-step explanation:

Step 1:

The plane is flying at a height of 25,000 feet and 45,000 feet away from the landing strip. Assume it lands with an angle of depression of x°.

So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 25,000 feet while the adjacent side measures 45,000 feet. The angle of the triangle is x°.

To determine the value of x, we calculate the tan of the given triangle.

Step 2:

The length of the opposite side = 25,000 feet.

The length of the adjacent side = 45,000 feet.

So x = 29.0521°. Since x < 30°, it is a safe landing.

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17