What does the graph of f(x)=x^2 look like if it is negative make sure to include shape and direction?

see the explanation

Step-by-step explanation:

we have

This is the equation of a vertical parabola open upward

The vertex represent a minimum

The vertex is the point (0,0)

The general shape of a parabola is the shape of a "pointy" letter "u," or a slightly rounded letter, "v."

If the function is negative

then

This is the equation of a vertical parabola open downward

The vertex represent a maximum

The vertex is the point (0,0)

see the attached figure to better understand the problem

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation: