A foreign student club lists as its members 2Canadians, 3 Japanese, 5 Italians, and 2 Germans. Ifa committee of 4 is selected at random, find the probability that(a) all nationalities are represented;(b) all nationalities except Italian are represented.

Step-by-step explanation:

(a)

Total number of members are (2 + 3 + 5 + 2) = 12.

From these 12 members 4 can be chosen in ways.

All the nationalities will be there only when one from each nationality will be there.

Hence, the required answer is .

(b)

There will be no Italians, hence all 4 should be chosen from (12 - 5) = 7 people.

From, 7 people, 4 can be chosen in ways.

Hence, in this case, the probability will be .

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph