A particular algebra text has a total of 1382 pages which is broken into two parts the second part of the book has 64 more pages than the first part how many pages are in each part of the book

the first part of the book has 659 pages and the second part has 723 pages

Step-by-step explanation:

First we have to raise 2 equations, one that shows us the relationship between one part of the book and the other, and another equation that shows us that together they give us the total of pages

x = second part

y = first part

x = y + 64

x + y = 1382

As the first equation tells us that x = y + 64 we will replace x in the second equation with (y + 64)

x + y = 1382

(y + 64) + y = 1382

y + y = 1382 - 64

2y = 1318

y = 1318/2

y = 659

now we replace in the first equation to y by its value

x = y + 64

x = 659 + 64

x = 723

so the first part of the book has 659 pages and the second part has 723

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above