Suppose a laboratory has a 26-gram sample of polonium-210.The half-life of polonium-210 is about days. a. How many half-lives of polonium-210 occur in 276 days? b. How much polonium is left in the sample after 276 days?

a) Two half lives, b)

Step-by-step explanation:

a) The polonium-210 has a half life of 138.4 days. Therefore, 1.994 half lives have past.  

b) Mass decay is described by the following exponential model:

The time constant for the isotope is:

The mass of the isotope after 276 days is:

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.

differentiate (x^14(x^-2)^4with respect to the variable

the parentheses don't balance in your input.

differentiate 0 with respect to

the final answer is

0

hope this