Lisa's pet shop has 2 fish tanks. Tank A contains smaller fish who are fed 1 gram of food each per day. Tank B contains 2/3 the number of fish that Tank A contains, Will Lisa ever feed both tanks the same amount of food?

Lisa will not be able to feed both tanks the same amount of food.

Step-by-step explanation:

This question is incomplete, here is the complete question :

"Lisa pet shop has 2 fish tank . Tank A contains smaller fish who were fed 1 gram of food each per day. Tank B contains larger fish who are fed 2 gram each per day. If tank B contains 2/3 the number of fish Tank A contains,will Lisa ever feed both tanks the same amount of food."

Let the number of fish in tank A = f

Lisa fed 1 gram of food each per day  = f × 1 = f

So,the number of fish in tank B =  

Lisa fed 2 gram of food each per day =

If both the tanks are fed with same amount of food then

⇒ 3f = 4f

⇒ 3 = 4

But 3 ≠ 4

Therefore, Lisa will not be able to feed both tanks the same amount of food.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

6 and 24

step-by-step explanation:

6 x 4 = 24