What is the equation of the line that passes through the points: (1,-2) and (3,-8)

y = -3x + 1

Step-by-step explanation:

Step 1:  Determine what the values of x1, x2, y1, y2 are

To find the slope use the formula, m =

(x1, y1) is (1, -2)

(x2, y2) is (3, -8)

Step 2:  Plug into the slope formula

m =

m =

m =

m =

m = -3

Step 3:  Determine what the values of y1, m, x1 in the point slope form

(y - y1) = m(x - x1)

(x1, y1) is (1, -2)

m = -3

Step 4:  Plug into the point slope form

(y - y1) = m(x - x1)

(y - (-2)) = -3(x - 1)

y + 2 - 2 = -3x + 3 - 2

y = -3x + 1

 y = -3x + 1

Step-by-step explanation:

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^