What are the roots of the equation?

x2=5x+14
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x=
or x=

the roots of the equation are x = 7 and x = -2

Step-by-step explanation:

To do this we first have to take that equation to the following form

Ax^2 + Bx + C = 0

x^2=5x+14

x^2 - 5x - 14 = 0

A = 1

B = -5

C = -14

-b(+-)√(b^2 - 4ac) / 2a

- (-5) (+-)√((-5^2) - 4 * 1 * (-14) ) / 2 * 1

5 (+-) √(25 + 56) / 2

5 (+-) √81  /2

(5 (+-) 9) /2

x1 = (5 + 9) / 2

x1 = 14/2

x1 = 7

x2 = (5 - 9) / 2

x2 = -4 / 2

x2 = -2

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

justin bieber ml.