Algebraically find the vertex of y= -2x^2 + 4x + 1?
pls show work

The vertex we want must be in the form of the point (-b/2a, y).

1. Find x.

x = -b/2a

x = -4/2(-2)

x = -4/(-4)

x = 1

2. Replace every x in the given function with 1 to find y.

y = -2(1)^2 + 4(1) + 1

y = -2 + 4 + 1

y = -2 + 5

y = 3

Our vertex is the point (1, 3).

Understand?

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|