Please help i put 15 points for this

(x-1) is a factor of the polynomial.

Step-by-step explanation:

Given:

f(x) = x³ + 6x² + 3x - 10

It is required to find which option is a factor of the given polynomial.

Factor the term (-10):

-10 = 1 * -10

     = -1 * 10

     = 2 * -5

     = -2 * 5

As the given options are: (x+1) , (x-1) , (x-2) , (x-10)

So, the possible roots are: -1 , 1 , 2 , 10

So,

we will Check the values -1 , 1 , 2 , 10 to find which of them will make f(x)= 0

If x = -1 ⇒ f(x) = (-1)³ + 6*(-1)² + 3*(-1) - 10 = -1 + 6 - 3 - 10 = -8

So, x = -1 is not one of the roots ⇒ (x-1) is not one of the factor.

If x = 1 ⇒ f(x) = 1³ + 6*1² + 3*1 - 10 = 1 + 6 + 3 - 10 = 0

So, x = 1 is one of the roots ⇒ (x-1) is one of the factor

The other values { 2 , 10} also are not the roots of the function

So, the answer is the second option

(x-1) is a factor of the polynomial.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

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step-by-step explanation: