A 2-ft-high and 6-ft-wide rectangular plate is submerged vertically in water so that the top is 1 ft below the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

F = 211312.5ft/lb.

Step-by-step explanation: Hydrostatic pressure is pressure caused by a fluid due to the force of gravity. It is calculated following the formula:

P = ρgh.

ρ is the fluid density (62.5 lb/ft³);

g is the gravitacional acceleration( 32.2ft/s²);

h is the height of the fluid columm;

P = 62.5.32.2.h

Pressure at h = 1ft:

P = 62.5.32.2.1

P = 2012.5 psi.

Now, hydrostatic force is F =

The pressure exerted on the surface is not constant. It depends on the height. So, to evaluate the force:

dF = P(h) dA

Since it a rectangular plate, dA = w.dh, where w is its width and equals 6 and dh is its height element.

That gives: dF = P(h)w.dh

= 2012.5.6. = 2012.5.6() = 12075() = 211312.5ft/lb.

angle uzt is congruent to angle tzy. angle vzw is congruent to angle yzx.

(credits to leowren)

step-by-step explanation:

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: