Array processing (elimination of three largest values) (one of many array reduction problems) The array a(1..n) contains arbitrary integers. Write a function reduce(a, n) that reduces the array a(1..n) by eliminating from it all values that are equal to three largest different integers. For example, if a=(9,1,1,6,7,1,2,3,3,5,6,6,6,6,7,9) then three largest different integers are 6,7,9 and after reduction the reduced array will be a=(1,1,1,2,3,3,5), n=7. The solution should have the time complexity O(n).

Step-by-step explanation:

# include <bits/stdc++.h>

using namespace std;

bool find3Numbers(int A[], int arr_size, int sum)

{

int l, r;

sort(A, A+arr_size);

for (int i=0; i<arr_size-2; i++)

{

l = i + 1;

r = arr_size-1;

while (l < r)

{

if( A[i] + A[l] + A[r] == sum)

{

printf("Triplet is %d, %d, %d", A[i],

A[l], A[r]);

return true;

}

else if (A[i] + A[l] + A[r] < sum)

l++;

else // A[i] + A[l] + A[r] > sum

r--;

}

}

return false;

}

int main()

{

int A[] = {1, 4, 3, 2, 10, 8};

int sum = 22;

int arr_size = sizeof(A)/sizeof(A[0]);

find3Numbers(A, arr_size, sum);

return 0;

}

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

mark brainliest!

there are infinitely many solutions.