In the following sequence, each number (except the first two) is the sum of the previous two number: 0, 1, 1, 2, 3, 5, 8, 13, This sequence is known as the Fibonacci sequence. Given the positive integers m and n (with m < n) create a list consisting of the portion of the Fibonacci sequence greater than or equal to m and less than or equal to n. For example, if m is 3 and n is 6, then the list would be [3, 5] and if m is 2 and n is 20, then the list would be [2, 3, 5, 8, 13]. Associate the list with the variable fib.

Fibonacci series ranging from m to n where m<n assuming n=200 and m=100 .

Step-by-step explanation:

#you have to produce a fibonacci series from 0 to n as follows:

k = [0,1]

fib=[]

n=200

m=100

for p in range(1, n+1):

   y = k[p]+k[p-1]

   if x > n:

      break

   else:

       k.append(y)

# Now to single out those fibonacci series between m and n in a list #associated with the variable fib, do the following:  

for p in range(0, len(k)):    # p ranging from 0 to the last index of k

   if k[p] >= m and k[p] <= n:

fib.append(k[p]) #append only those series within m and n to the    

                           #variable fib

print fib   #this will display the list created

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.