In a murder investigation, the temperature of the corpse was 32.5°C at 1:30 pm and 30.3°C an hour later. Normal body temperature is 37.0°C and the temperature of the surroundings was 20.0°C. When did the murder take place?

Step-by-step explanation:

Given that in a murder investigation, the temperature of the corpse was 32.5°C at 1:30 pm and 30.3°C an hour later.

Normal body temperature is 37.0°C and the temperature of the surroundings was 20.0°C.

As per Newton law of cooling we have

is the temperature at time t.

Substitute this for given two information to find k and T0

Divide I equation by II to get

Using this we find t at 1.30 p.m.

i.e. approximately 1.6 hours or 1 hour 36 minutes lapsed at 1.30

Time of murder is

11 hrs 54 minutes.

need more detail

step-by-step explanation:

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(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week