About 42% of people who get their eyes examined are found to be nearsighted (unable to see objects at a distance). What is the probability of an ophthalmologist examining five people until he finds the first patient who is nearsighted? (0.42)5 (0.58)4(0.42)1 (0.42)4(0.58)1 (0.58)5 1 − (0.42)4

(0.58)⁴ (0.42)¹

Step-by-step explanation:

42% of people who get their eyes examined are nearsighted.

So 58% of people who get their eyes examined are not nearsighted.

The probability that the ophthalmologist examines 4 people who are not near sighted, followed by 1 person who is nearsighted, is:

P = (0.58)⁴ (0.42)¹

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dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3