Plz solve this
ans = 4400

The total surface area of the solid is 4651 sq cm

Step-by-step explanation:

Given,

The diameter of the base = 16 cm

Length of the cylindrical part (h) = 75 cm

The height of the solid = 90 cm

So, the radius of the base(r) = cm = 8 cm

The height of the cone = 90 - 75 cm = 15 cm

The slanting height(l) of the cone = cm = 17 cm [ by Pythagoras theorem]

To find the total surface area of the solid

The solid consists of two separate solids that are a cylinder and a cone.

So, total surface area (TSA) of the solid = TSA of cylinder + TSA of cone

To find the TSA pf cylinder

Formula

TSA of cylinder = 2πrh +2πr

=2πr(r+h)

=2 ××8×(8+75) sq cm

= 4173.7 sq cm (approx)

Again,

To find the TSA pf cone

Formula

TSA of cone = πrl +2πr

=πr(l+2) sq cm

= ×8×(17+2) sq cm

= 477.7 sq cm (approx)

Hence, total surface area (TSA) of the solid = 4173.7 sq cm + 477.7 sq cm

= 4651.4 sq cm

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere