An 16 16-oz jar of peanut butter in the shape of a right circular cylinder is 7 7 in. high and 5 5 in. in diameter and sells for $ 1.60 1.60. In the same store, a 29 29-oz jar of the same brand is 7 and one half 7 1 2 in. high and 5 and one fourth 5 1 4 in. in diameter. If the cost is directly proportional to volume, what should the price of the larger jar be? If the cost is directly proportional to weight, what should the price of the larger jar be? If the cost is directly proportional to volume, the price of the larger jar should be $ nothing

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

Considering the 16 oz jar,

h = 7 inches

Diameter = 5 inches

Radius = diameter/2 = 5/2

r = 2.5 inches

Volume = 3.14 × 2.5² × 7 = 137.375 inches³

Considering the 29 oz jar,

h = 7.5 inches

Diameter = 5.25 inches

Radius = diameter/2 = 5.25/2

r = 2.625 inches

Volume = 3.14 × 2.625² × 7.5 = 162.27 inches³

1) If the cost is directly proportional to volume, then

If 137.375 inches³ cost $1.6

then 162.27 inches³ should cost

(162.27 × 1.6)/137.375 = $1.89

The price of the larger jar would be $1.89

2) If the cost is directly proportional to weight, then

If 16 oz cost $1.6, then

29 oz would cost

(29 × 1.6)/16 = $2.9

The price of the larger jar would be $2.9

answer: it's a

step-by-step explanation:

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply