1st Question: Dominic pays 7% interest on his $18,000 college loan and 12% interest on his $14,000 car loan. What average interest rate does he pay on the total $32,000 he owes? (Round your answer to the nearest tenth of a percent.)

2nd Question: The ice rink sold 95 tickets for the afternoon skating session, for a total of $828. General admission tickets cost $10 each and youth tickets cost $8 each. How many general admission tickets and how many youth tickets were sold?

1) The average interest rate he will pay on the total $32,000 he owes 9.2%

2) General tickets is 34 and youth tickets is 61

Step-by-step explanation:

1st Question:

Total money owed = $32,000

Interest paid on $18,000 is 7% ==> 18,000 x 0.07 = 1,260

Interest paid on $14,000 is 12% ==> 14,000 x 0.12 = 1,680

To find Average interest rate:

Let 'X' be interest paid on $32,000 ==> 32,000*X

Total interest paid = Sum of all interests

32,000*X = 1,260 + 1,680

32,000*X = 2,940

X = 0.0919

∴ X = 9.2%

2nd Question

Value of 95 tickets is $828

Youth ticket cost is $8

General admission cost is $10

Let 'Y' be Number of youth tickets sold, Number of general admission tickets is 95 - Y since the total number of ticket is 95.

Value of 95 - Y general admission tickets is (95 - Y)10

Value of Y youth tickets is 8Y

Total value is $828

(95-Y)10 + 8Y = 828

950 - 10Y + 8Y = 828

122  = 2Y

Y = 61

Recall that, number of general admission tickets is 95 - Y ==> 95 - 61 ==> 34

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation: