The lees have three children. The oldest is three times older than the youngest. The middle child is eight years older than the youngest. If the sum of the ages is 43, how old is each child?

21, 15, 7

Step-by-step explanation:

you can write it as a a system of equations

x=older child y= younger child m=middle child

x=3y (oldest age is 3 times the youngest)

m=y+8 (middle is 8 years older than the youngest)

x+y+m=43 (sum of their ages = 43)

rewrite the third in terms of the youngest

3y + y + (y+8) = 43

5y = 35 therefore y=35/7=7

then

m=y+8= 7+8= 15

x=3y=3*7=21

i believe the answer to be 48

step-by-step explanation: