Andrew has a bag that contains 8 blue marbles, 6 red marbles, and 10 green marbles. He selects a marble, replaces it in the bag, and then selects another. What is the probability that the first marble is blue and the second marble is red?
A. 1/2
B. 7/12
C. 1/8
D. 1/12

Andrew has 8 blue marbles, 6 red, and 10 green.

8+6+10 = 24 marbles in total.

If he selects a marble, replaces it in the bag, and then selects another, we're being asked the probability that the first marble is blue and the second is red.

You have a 6/24 (1/4) chance of the first one being red.

So you have a 8/24 (1/3) chance of the second being blue.

Since replacement occurs, we multiply them together:

1/4 * 1/3 = 1/12.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!