If an object is shot upward with an initial velocity, v 0 v0 , in feet per second (ft/s), the velocity, v, in ft/s is given by the formula v= v 0 −32t v=v0−32t , where t is time in seconds. Find the initial velocity of an object if the velocity after 3 3 seconds is 28ft/s 28⁢ft/s

We are given a velocity equation, and from that, we want to find the initial velocity such that we know the velocity for a given time.

We will see that the initial velocity is 124 ft/s

Let's see how to solve this:

We have that the velocity equation:

v(t) = v₀ - (32 ft/s^2)*t

Where I added the units of the gravitational acceleration, which are in ft over seconds squared.

We want to get the value of the initial velocity, v₀, given that after 3 seconds the velocity is 28ft/s.

This means that:

v(3s) = 28 ft/s = v₀ - (32 ft/s^2)*3s

We can solve this for v₀:

28 ft/s = v₀ - (32 ft/s^2)*3s

28 ft/s + (32 ft/s^2)*3s = v₀

124 ft/s = v₀

So we can see that the initial velocity is 124 ft/s

If you want to learn more, you can read:

link

1084 ft/s

Step-by-step explanation:

28 = v₀-32(33)

v₀ = 28 +32(33)

v₀ = 1084

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64