A clothing store has a rectangular clearance section with a length that is twice the width w. During a sale, the section is expanded to an area of (2w^2 + 11w + 12) ft^2. Find the amount of the increase in the length and width of the clearance section.

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Step-by-step explanation:

step 1

The original area of the rectangular clearance section is equal to

----> equation A

we know that

The length is twice the width

----> equation B

substitute equation B in equation A

step 2

During a sale, the section is expanded to an area of

so

To find out the amount of the increase in the length and width of the clearance section, subtract the areas

therefore

The amount of the increased area is

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

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step-by-step explanation: