Find, to the nearest tenth of a degree, all values of x for the interval 0 is less then or equal to x which is less then or equal to 360 that satisfy the equation 5sin^2x-9cosx-3=0
(REFER TO PICTURE ATTACHED)

Step-by-step explanation:

5sin^2x-9cosx-3=0  ⇔ 5(1 -cos^2x) - 9cosx - 3 = 0

                                ⇔ -5cos^2x - 9cosx + 2 = 0

                                ⇔ 5cos^2x + 9cosx - 2 = 0

now we need to solve : 5x² - 9x + 2 = 0

5x² - 9x + 2 = 0 ⇔ 5(x - 0.2)(x + 2) = 0

                         ⇔ x = 0.2 or x = -2

cosx = -2 (impossible)

cosx = 0.2 ⇔ cos⁻¹(0.2) = 78.463040967184

cos(360-78.463040967184) = 0.2

360-78.463040967184 = 281.536959032816

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1