A bag of 1313 marbles contains 77 marbles with red on them, 44 with blue on them, 55 with green on them, and 33 with red and green on them. What is the probability that a randomly chosen marble has either green or red on it

The probability of selecting a red or green marble is 0.6923.

Step-by-step explanation:

Let's denote the events as follows:

R = a red marble is chosen

G = a green marble is chosen

The information provided is:

n (R) = 7

n (G) = 5

n (R ∩ G) = 3

Total number of marbles in the bag is, N = 13.

The probability of an event E is:

Compute the probability of selecting a red or green marble as follows:

P (R ∪ G) = P (R) + P (G) - P (R ∩ G)

Thus, the probability of selecting a red or green marble is 0.6923.

9 x 8 divided by (5-3)=36

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4