Suppose that an airline uses a seat width of 16.2 in. Assume men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 1 in. Complete parts (a) through (c) below. (a) Find the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.2 in. The probability is 0.0446 (Round to four decimal places as needed.) (b) If a plane is filled with 128 randomly selected men, find the probability that these men have a mean hip breadth greater than 16.2 in The probability is (Round to four decimal places as needed.)

Step-by-step explanation:

Given  that an airline uses a seat width of 16.2 in. Assume men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 1 in.

X is the hip breadth of men

X is N(14.5, 1)

We can convert X into std normal variate Z as

a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.2 in.

=

b) Here n =128 and each person is independent of the other

Hence for any person to have hip greater than 16.2 inches is binomial with constant prob = 0.0446

the probability that these men have a mean hip breadth greater than 16.2 in

N(14.5, 1/sqrt 128)

i.e. very unusual event.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )